Optimal. Leaf size=159 \[ \frac{2 (5 A-B) \sin (c+d x) \sqrt{a \cos (c+d x)+a}}{15 a d}-\frac{4 (5 A-7 B) \sin (c+d x)}{15 d \sqrt{a \cos (c+d x)+a}}+\frac{\sqrt{2} (A-B) \tanh ^{-1}\left (\frac{\sqrt{a} \sin (c+d x)}{\sqrt{2} \sqrt{a \cos (c+d x)+a}}\right )}{\sqrt{a} d}+\frac{2 B \sin (c+d x) \cos ^2(c+d x)}{5 d \sqrt{a \cos (c+d x)+a}} \]
[Out]
________________________________________________________________________________________
Rubi [A] time = 0.384485, antiderivative size = 159, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 6, integrand size = 33, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.182, Rules used = {2983, 2968, 3023, 2751, 2649, 206} \[ \frac{2 (5 A-B) \sin (c+d x) \sqrt{a \cos (c+d x)+a}}{15 a d}-\frac{4 (5 A-7 B) \sin (c+d x)}{15 d \sqrt{a \cos (c+d x)+a}}+\frac{\sqrt{2} (A-B) \tanh ^{-1}\left (\frac{\sqrt{a} \sin (c+d x)}{\sqrt{2} \sqrt{a \cos (c+d x)+a}}\right )}{\sqrt{a} d}+\frac{2 B \sin (c+d x) \cos ^2(c+d x)}{5 d \sqrt{a \cos (c+d x)+a}} \]
Antiderivative was successfully verified.
[In]
[Out]
Rule 2983
Rule 2968
Rule 3023
Rule 2751
Rule 2649
Rule 206
Rubi steps
\begin{align*} \int \frac{\cos ^2(c+d x) (A+B \cos (c+d x))}{\sqrt{a+a \cos (c+d x)}} \, dx &=\frac{2 B \cos ^2(c+d x) \sin (c+d x)}{5 d \sqrt{a+a \cos (c+d x)}}+\frac{2 \int \frac{\cos (c+d x) \left (2 a B+\frac{1}{2} a (5 A-B) \cos (c+d x)\right )}{\sqrt{a+a \cos (c+d x)}} \, dx}{5 a}\\ &=\frac{2 B \cos ^2(c+d x) \sin (c+d x)}{5 d \sqrt{a+a \cos (c+d x)}}+\frac{2 \int \frac{2 a B \cos (c+d x)+\frac{1}{2} a (5 A-B) \cos ^2(c+d x)}{\sqrt{a+a \cos (c+d x)}} \, dx}{5 a}\\ &=\frac{2 B \cos ^2(c+d x) \sin (c+d x)}{5 d \sqrt{a+a \cos (c+d x)}}+\frac{2 (5 A-B) \sqrt{a+a \cos (c+d x)} \sin (c+d x)}{15 a d}+\frac{4 \int \frac{\frac{1}{4} a^2 (5 A-B)-\frac{1}{2} a^2 (5 A-7 B) \cos (c+d x)}{\sqrt{a+a \cos (c+d x)}} \, dx}{15 a^2}\\ &=-\frac{4 (5 A-7 B) \sin (c+d x)}{15 d \sqrt{a+a \cos (c+d x)}}+\frac{2 B \cos ^2(c+d x) \sin (c+d x)}{5 d \sqrt{a+a \cos (c+d x)}}+\frac{2 (5 A-B) \sqrt{a+a \cos (c+d x)} \sin (c+d x)}{15 a d}+(A-B) \int \frac{1}{\sqrt{a+a \cos (c+d x)}} \, dx\\ &=-\frac{4 (5 A-7 B) \sin (c+d x)}{15 d \sqrt{a+a \cos (c+d x)}}+\frac{2 B \cos ^2(c+d x) \sin (c+d x)}{5 d \sqrt{a+a \cos (c+d x)}}+\frac{2 (5 A-B) \sqrt{a+a \cos (c+d x)} \sin (c+d x)}{15 a d}-\frac{(2 (A-B)) \operatorname{Subst}\left (\int \frac{1}{2 a-x^2} \, dx,x,-\frac{a \sin (c+d x)}{\sqrt{a+a \cos (c+d x)}}\right )}{d}\\ &=\frac{\sqrt{2} (A-B) \tanh ^{-1}\left (\frac{\sqrt{a} \sin (c+d x)}{\sqrt{2} \sqrt{a+a \cos (c+d x)}}\right )}{\sqrt{a} d}-\frac{4 (5 A-7 B) \sin (c+d x)}{15 d \sqrt{a+a \cos (c+d x)}}+\frac{2 B \cos ^2(c+d x) \sin (c+d x)}{5 d \sqrt{a+a \cos (c+d x)}}+\frac{2 (5 A-B) \sqrt{a+a \cos (c+d x)} \sin (c+d x)}{15 a d}\\ \end{align*}
Mathematica [A] time = 0.319758, size = 94, normalized size = 0.59 \[ \frac{2 \cos \left (\frac{1}{2} (c+d x)\right ) \left (15 (A-B) \tanh ^{-1}\left (\sin \left (\frac{1}{2} (c+d x)\right )\right )+\sin \left (\frac{1}{2} (c+d x)\right ) (2 (5 A-B) \cos (c+d x)-10 A+3 B \cos (2 (c+d x))+29 B)\right )}{15 d \sqrt{a (\cos (c+d x)+1)}} \]
Antiderivative was successfully verified.
[In]
[Out]
________________________________________________________________________________________
Maple [A] time = 2.135, size = 240, normalized size = 1.5 \begin{align*}{\frac{1}{15\,d}\cos \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) \sqrt{a \left ( \sin \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) \right ) ^{2}} \left ( 24\,B\sqrt{2}\sqrt{a \left ( \sin \left ( 1/2\,dx+c/2 \right ) \right ) ^{2}}\sqrt{a} \left ( \sin \left ( 1/2\,dx+c/2 \right ) \right ) ^{4}-20\,\sqrt{2}\sqrt{a \left ( \sin \left ( 1/2\,dx+c/2 \right ) \right ) ^{2}}\sqrt{a} \left ( A+B \right ) \left ( \sin \left ( 1/2\,dx+c/2 \right ) \right ) ^{2}+15\,\sqrt{2}\ln \left ( 4\,{\frac{\sqrt{a}\sqrt{a \left ( \sin \left ( 1/2\,dx+c/2 \right ) \right ) ^{2}}+a}{\cos \left ( 1/2\,dx+c/2 \right ) }} \right ) aA-15\,\sqrt{2}\ln \left ( 4\,{\frac{\sqrt{a}\sqrt{a \left ( \sin \left ( 1/2\,dx+c/2 \right ) \right ) ^{2}}+a}{\cos \left ( 1/2\,dx+c/2 \right ) }} \right ) aB+30\,B\sqrt{2}\sqrt{a \left ( \sin \left ( 1/2\,dx+c/2 \right ) \right ) ^{2}}\sqrt{a} \right ){a}^{-{\frac{3}{2}}} \left ( \sin \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) \right ) ^{-1}{\frac{1}{\sqrt{ \left ( \cos \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) \right ) ^{2}a}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Maxima [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Fricas [A] time = 1.72292, size = 446, normalized size = 2.81 \begin{align*} \frac{4 \,{\left (3 \, B \cos \left (d x + c\right )^{2} +{\left (5 \, A - B\right )} \cos \left (d x + c\right ) - 5 \, A + 13 \, B\right )} \sqrt{a \cos \left (d x + c\right ) + a} \sin \left (d x + c\right ) - \frac{15 \, \sqrt{2}{\left ({\left (A - B\right )} a \cos \left (d x + c\right ) +{\left (A - B\right )} a\right )} \log \left (-\frac{\cos \left (d x + c\right )^{2} + \frac{2 \, \sqrt{2} \sqrt{a \cos \left (d x + c\right ) + a} \sin \left (d x + c\right )}{\sqrt{a}} - 2 \, \cos \left (d x + c\right ) - 3}{\cos \left (d x + c\right )^{2} + 2 \, \cos \left (d x + c\right ) + 1}\right )}{\sqrt{a}}}{30 \,{\left (a d \cos \left (d x + c\right ) + a d\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Giac [A] time = 1.74188, size = 213, normalized size = 1.34 \begin{align*} -\frac{\frac{15 \,{\left (\sqrt{2} A - \sqrt{2} B\right )} \log \left ({\left | -\sqrt{a} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + \sqrt{a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} + a} \right |}\right )}{\sqrt{a}} - \frac{2 \,{\left (15 \, \sqrt{2} B a^{2} -{\left (10 \, \sqrt{2} A a^{2} - 20 \, \sqrt{2} B a^{2} +{\left (10 \, \sqrt{2} A a^{2} - 17 \, \sqrt{2} B a^{2}\right )} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2}\right )} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2}\right )} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )}{{\left (a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} + a\right )}^{\frac{5}{2}}}}{15 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]